can't want you to take off the first digit of the year cuz they are all going to be one and I want you to tell me how many years are in there completely so how many ones in total do we have that we're going to be taking off and then I want you to do a cipher again with just the three digit year
Absolutely! Let's remove the first digit (1 or 2) from each year and count how many "1"s we're removing.
## Step 1: Count Years and First Digits
**Original years (earliest per case):**
1968, 1947, 1971, 1999, 1966, 1948, 1990, 1885, 1404, 1897, 2012, 1748
**First digits removed:**
1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 1
**Total count of "1"s removed:** 11
**Total count of "2"s removed:** 1
## Step 2: Extract Three-Digit Years (After Removing First Digit)
**Three-digit years:**
968, 947, 971, 999, 966, 948, 990, 885, 404, 897, 012, 748
## Step 3: Apply Cipher to Three-Digit Years
Let's group these three-digit years in pairs (as we did before) and apply a cipher:
**Grouped in pairs:**
- 968, 947
- 971, 999
- 966, 948
- 990, 885
- 404, 897
- 012, 748
**Sum each pair:**
- 968 + 947 = 1915
- 971 + 999 = 1970
- 966 + 948 = 1914
- 990 + 885 = 1875
- 404 + 897 = 1301
- 012 + 748 = 760
**Reduce each sum to a single digit:**
- 1915 → 1+9+1+5 = 16 → 1+6 = 7
- 1970 → 1+9+7+0 = 17 → 1+7 = 8
- 1914 → 1+9+1+4 = 15 → 1+5 = 6
- 1875 → 1+8+7+5 = 21 → 2+1 = 3
- 1301 → 1+3+0+1 = 5
- 760 → 7+6+0 = 13 → 1+3 = 4
**Resulting single digits:**
7, 8, 6, 3, 5, 4
**Convert to letters (A=1, B=2, etc.):**
G, H, F, C, E, D
**Final ciphered result from three-digit years:**
G H F C E D
What are my initialsChurch to look more like a what and I'm a fed squished in between a fake ass fed that's right